Find the dimensions of a rectangle with a perimeter of 52cm if it's length is 4cm more than its width

So the perimeter (P) of a rectangle would be:

P = 2L+2W

L being the length and W being the width.

The problem says the length is 4cm more than the width, so L = 4+W.

So if we substitute L with 4+W, we get:

P = 2 (4+W) + 2W

Use the Distributive Property

P = 8+2W+2W

Combine like terms

P=8+4W

Since we're given the perimeter, we could replace P with 52. So:

52=8+4W

Subtract 8 to both sides

44=4W

Divide 4 to both sides

11=W

Therefore, the width is 11cm

And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm

Thus, the dimensions of the rectangle are 15cm by 11cm