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19 January, 14:22

If QR is 7 less than twice X, RS is 61 less than 5 times x, and QS is 11 more than x, find X and the measure of each side.

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  1. 19 January, 17:48
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    We can't find the answer unless there's the total amount of circumstances.

    Step-by-step explanation:

    QR = 2x-7

    RS = x-61

    QS = x+11

    2x+7+x-61+x+11

    ? = 4x-43
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