A car is moving with an initial velocity of 10 mph accelerates at the rate of a (t) = 2.5t mph per second for 5 seconds. How fast is the car going when the 5 seconds are up?

22.5 mph

Step-by-step explanation:

According to the question, a car is moving with an initial velocity of 10 mph accelerates at the rate of a (t) = 2.5t mph per second for 5 seconds and we are asked to find out how fast is the car going when the 5 seconds are up?

The formula to be applied here so as to derive our answer is

v = u + at

Where v is the final velocity, u is the initial velocity, acceleration and t is the time

V = ?

U = 10

A = 2.5t ≈ 2.5 * 5 = 12.

T = 5

10 + 12.5 = 22.5 mph

The car is going up at a speed of 22.5 mph

Step-by-step explanation:

In this question, we are asked to calculate the speed of a moving car which started moving at an initial velocity for a specific period of time.

To calculate this, we use one of the basic equations of motion;

v = u + at

Where v is the final velocity, u is the initial velocity and t is the time

From the question, we can identify the parameters as follows;

v = ?

u = 10mph

a = 2.5t mph per second for 5 seconds.

Hence a here would be 2.5 * 5 = 12.5

Now, let's put these values in the equation

v = 10 + 12.5

v = 22.5 mph