In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=71°, and JH = 2 feet. Find the length of IJ to the nearest tenth of a foot.

Question

Mathematics

Nash Barton

7 May, 14:36

In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=71°, and JH = 2 feet. Find the length of IJ to the nearest tenth of a foot.

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Answers (1)

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Reece Marquez · Answer 1

IJ = 5.81 ft

To the nearest tenth = 10 ft

Step-by-step explanation:

ΔHIJ is a right angle triangle.

∠J=90°

∠H=71°

JH = 2

IJ = ?

∠I = 180 - (∠J+∠H)

∠l = 180 - (90+71)

∠l = 180 - 161

∠l = 19°

Tan ∠l =. JH / IJ

Tan 19 = 2/IJ

0.3443 * IJ = 2

IJ = 2/0.3443

IJ = 5.81 ft

To the nearest tenth = 10 ft