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7 December, 19:58

What is the vertex of the graph of the quadratic function y = x^2 6x 10? (3, - 1) (-3, - 1) (-3, 1) (3, 1)

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  1. 7 December, 23:17
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    Y = x^2 + 6x + 10

    y = (x+6/2) ^2-6/2^2+10

    y = (x+3) ^2-3^2+10

    y = (x+3) ^2-9+10

    y = (x+3) ^2+1
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