Consider the function: f (x) = x^2-4x-12 it's vertex is: (_,_)

it's largest x-intercept is x=_.

it's y-intercept is y=_.

f (x) = x^2-4x-12

factor

(x-6) (x+2)

The zeros are at 6, - 2

to find the vertex find the axis of symetry

the axis of symmerty is at (-2+6) / 2=4/2 = 2

x=2

to find the y coordinate, put it into the equation

y = 2^2 - 4 (2) - 12

= 4-8-12

= 4-20

= - 16

vertex (2,-16)

largest x intercept x=6

y intercept - 12