How do i solve x squared = 4x - 5

x = 2 ±i

Step-by-step explanation:

x^2 = 4x-5

Subtract 4x from each side

x^2 - 4x = 4x-5 - 4x

x^2 - 4x = - 5

Complete the square

Take the coefficient of the x term, divide by 2 and square it

-4/2 = 2 2^2 = 4

Add 4 to each side

x^2 - 4x+4 = - 5 + 4

The left side is (x-coefficient of the x term/2) ^2

(x-2) ^2 = - 1

Take the square root of each side

sqrt ((x-2) ^2) = sqrt (-1)

x-2 = ±i

Add 2 to each side

x-2+2 = 2 ±i

x = 2 ±i