The greater of two numbers is six more than 4 times the smaller. Their sum is 41. Find the number

smaller number is 7

larger number is 35

Step-by-step explanation:

Let the smaller number be x

Given that greater number is 6 more than 4 times the smaller number.

If x is value of smaller number then 4 times the smaller number is 4*x = 4x

six more than 4 times the smaller number will be 6+4x.

Thus larger number is 6+4x

Sum of smaller and larger no is 41.

Substituting the value of smaller and larger number in sum we have

x+6+4x = 41

=> 5x+6 = 41

=> 5x = 41-6

=> 5x = 35

=>x = 35/5 = 7

Thus smaller number is x = 7

larger number = 4x+6 = 4*7+6 = 35