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9 March, 07:19

What are the vertex, focus, and directrix of the parabola with equation y = x^2 - 10x + 33?

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  1. 9 March, 10:22
    0
    Opens up so

    (x-h) ^2=4P (y-k)

    complete the square with the x term

    take 1/2 of - 10 and square it and add that to both sides

    y+25=x^2-10x+25+33

    factor perfect square

    y+25 = (x-5) ^2+33

    minus 33 both sides

    y-8 = (x-5) ^2

    force factor out a 4

    4 (1/4) (y-8) = (x-5) ^2

    (x-5) ^2=4 (1/4) (y-8)

    vertex is (5,8)

    distance from directix is P or 1/4 or 0.25

    since opens up, directix is ycoordinate-0.25 aka y=7.75 is directix

    focus = (5,8+0.25) = (5,8.25)

    vertex = (5,8)

    directix: y=7.75

    focus: (5,8.25)
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