At the gym, Polina put 4 five-pound weights onto a barbell that weighed 22 pounds without any weights on it. If Polina lifted the barbell with both arms, which expression can be used to determine the weight that each arm was lifting?

[ (4 * 5) : 2] + 22

(4 * 5) : 2 + 22

[22 + 4 * 5] : 2

22 + (4 * 5) : 2

Question

Mathematics

Finnegan Glenn

11 June, 01:34

At the gym, Polina put 4 five-pound weights onto a barbell that weighed 22 pounds without any weights on it. If Polina lifted the barbell with both arms, which expression can be used to determine the weight that each arm was lifting?

[ (4 * 5) : 2] + 22

(4 * 5) : 2 + 22

[22 + 4 * 5] : 2

22 + (4 * 5) : 2

+3

Answers (1)

Know the Answer?

Annie Smith · Answer 1

D. 22 + (4*5) : 2

Step-by-step explanation:

Four 5 pound weight = (4*5)

Barbell weighed 22 pounds

={ (4*5) + 22}

Paulina lifted it with both arms

Both arms=2

{ (4*5) + 22}/2

It can be rewritten as

22 + (4*5) : 2