How do I solve 12=3 (2x-10) + 6

Question

Mathematics

Trevin Bailey

25 January, 11:34

How do I solve 12=3 (2x-10) + 6

+2

Answers (2)

Know the Answer?

Leonardo Curtis · Answer 1

Hello.

1. switch sides

3 (2x-10) + 6=12

2. subtract 6 from both sides

3 (2x-10) + 6-6=12-6

3. simplfy

3 (2x-10) = 6

4. divide both sides by 3

3 (2x-10) / 3=6/3

5. simpfly

2x-10=2

6. add 10 to both sides

2x-10+10=2+10

7 simpfly

2x=12

Answer=6

have a nice day

Raymond Little · Answer 2

Subtract 6 from both sides and you get 6=3 (2x-10)

Divide both sides by 3 and you get 6/ 3 =2x-10 and 6/3=2 so 2=2x-10

then add 10 to both sides 2+10=2x and you get 12=2x divide by 2

x=6 then check your answer and you get 12=12