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Yesterday, 05:17

Evaluate 6t - 20-32u when t = 6 and u = 1/5

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Answers (2)
  1. Yesterday, 09:10
    0
    48/5 = 9 4/5

    Step-by-step explanation:

    first substitute the variable

    6 (6) - 20-32 (1/5)

    36-20-32/5

    16-32/5

    get the both numbers to have the same denominator

    16 times 5/5 = 80/5

    now subtract the both numbers

    80/5-32/5 = 48/5

    48/5 = 9 4/5
  2. Yesterday, 09:12
    0
    48/5

    Step-by-step explanation:

    6t - 20-32u

    Let t = 6 and u = 1/5

    6*6 - 20 - 32 (1/5)

    Multiply

    36 - 20 - 32/5

    16 - 32/5

    Get a common denominator

    80/5 - 32/5

    48/5
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