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Francis Vega
Yesterday, 05:17
Evaluate 6t - 20-32u when t = 6 and u = 1/5
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Paige
Yesterday, 09:10
0
48/5 = 9 4/5
Step-by-step explanation:
first substitute the variable
6 (6) - 20-32 (1/5)
36-20-32/5
16-32/5
get the both numbers to have the same denominator
16 times 5/5 = 80/5
now subtract the both numbers
80/5-32/5 = 48/5
48/5 = 9 4/5
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Liliana Mayo
Yesterday, 09:12
0
48/5
Step-by-step explanation:
6t - 20-32u
Let t = 6 and u = 1/5
6*6 - 20 - 32 (1/5)
Multiply
36 - 20 - 32/5
16 - 32/5
Get a common denominator
80/5 - 32/5
48/5
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