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16 August, 14:18

For the geometric sequence 3, 6, 12 ..., find the 13th term and state the common ratio of the sequence

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  1. 16 August, 17:50
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    Common ratio, is r=6/3=12/6=2

    Answer: common ratio 2

    First term a₁ = 3

    nth term aₙ = a₁rⁿ⁻¹ = 3 (2ⁿ⁻¹)

    13th term = 3 (2¹²) = 12288

    Answer: 13th term is 12,288
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