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15 February, 02:05

X^2 - 16x + y^2 - 36=0 what is the center of this circle

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Answers (1)
  1. 15 February, 03:18
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    (8, 18)

    Step-by-step explanation:

    Complete the square twice:

    x^2 - 16x + y^2 - 36 = 0

    x^2 - 16x + 8^2 + y^2 - 36 + 18^2 = 0 + 8^2 + 18^2

    (x-8) ^2 + (y-18) ^2 = 388

    Center: (8, 18)
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