The opposite angles of a quadrilateral inscribed in a
circle are supplementary:
mZQ + m2S 180°
mZS = 180° - mZQ = 180° - 68° = 112°
mZR + m2T = 180°
(3x + 40) + (5x - 52) = 180°
Solving for x, x = 24.
Substituting the value of x in the expressions for mZR and
mZT, mZR = 112º and mZT = 68°. Enter the correct answer.
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