What is the formula for the following arithmetic sequence?

12, 6, 0, - 6, ...

an = 12 + (-6) (n - 1)

an = - 6 + 12 (n - 1)

an = 6 + 12 (n - 1)

an = 12 + 6 (n - 1)

an = 6 + 12 (n - 1) is the answer

Correct answer: First answer - aₙ = 12 + (-6) (n - 1)

Step-by-step explanation:

Given: arithmetic sequence 12, 6, 0, - 6, ...

First term a₁ = 12

Second term a₂ = 6

Third term a₃ = 0

we will get the difference

d = a₂ - a₁ = a₃ - a₂ = 6 - 12 = 0 - 6 = - 6

d = - 6

a₂ = a₁ + d

a₃ = a₂ + d = a₁ + 2 d

a₄ = a₃ + d = a₁ + 3 d

...

aₙ = a₁ + (n - 1) d

aₙ = 12 + (n - 1) (-6) = 12 + (-6) (n - 1)

aₙ = 12 + (-6) (n - 1)

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