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10 February, 06:16

If n = 8 and 16 · 2^m = 4^ (n - 8), then m = ?

F. - 4

G. - 2

H. 0

J. 1

K. 8

+4
Answers (1)
  1. 10 February, 07:59
    0
    16 · 2^m = 4^ (n - 8)

    get everything with the same base)

    2^4 * 2^m = 2^2^ (n-8)

    2^ (4+m) = 2^ (2 (n-8))

    4+m = 2 (n-8)

    4+m = 2n-16

    m = 2n-16-4

    if n=8

    m = 2n-20

    m = 16-20

    m=-4

    Choice F
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