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11 December, 07:13

Calculate the sum of the first 42 terms in the sequence. - 10, 2, 14, 26,

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  1. 11 December, 10:45
    0
    17,661

    Step-by-step explanation:

    -10, 2, 14, 26

    T1 = a = - 10

    T2 = 2

    T3 = 14

    T4 = 26

    Lets find the common difference

    T2 - T1 = T3 - T2

    2 - (-10) = 12 = 14 - 2 = 12

    common difference d = 12

    therefore, this is an arithmetic progression

    Sum of first 42 terms

    S42 = n/2 [2a + (n - 1) * d]

    where n = 42

    slot in the values

    S42 = 42/2 [2 * (-10) + (42 - 1) * 12]

    S42 = 21[ - 20 + (41*12) ]

    S42 = 21 (-20 + 861)

    S42 = 21 (841)

    S42 = 17,661
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