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31 August, 09:09

If y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 82

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  1. 31 August, 09:58
    0
    y = 41/6

    Step-by-step explanation:

    This means that y = kx. k is a constant.

    6 = k*72

    and.

    y = k*82 ...

    k = 6/72 = 1/12

    y = 82/12

    y = 41/6
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