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10 April, 15:13

Find a polynomial of degree 3 with real coefficients and zeros of - 3,-1, and 4, for which f (- 2) = -18.

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  1. 10 April, 17:18
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    Step-by-step explanation:

    hello:

    f (x) = a (x+3) (x+1) (x-4)

    now calculate a if f (-2) = 18 means when x=-2 y=18

    so : a (-2+3) (-2+1) (-2-4) = 18

    6a=18

    a=18/6=3

    conclusion : f (x) = 3 (x+3) (x+1) (x-4)
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