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18 April, 20:34

Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:

the odd digits must occupy even positions (i. e. 2nd, 4th and 6th) and the even digits must occupy odd positions (i. e. 1st, 3rd and 5th)

+5
Answers (2)
  1. 18 April, 20:56
    0
    729 is the correct answer
  2. 18 April, 21:50
    0
    the answer your looking for is 7
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