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15 January, 23:32

There are 25 stationary bikes and treadmills altogether. If there are 7 more stationary bikes than treadmills, how many of each are there?

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  1. 16 January, 00:46
    0
    You'd solve this equation by writing two equations. I'd call treadmills x and stationary bikes as y. The two equation would be x+y=25 and y=x+7. You'd then plug the second equation into the first equation to get x + (x+7) = 25. You'd combine like terms, making it 2x+7=25. You'd then subtract 7 from both sides to get 18 and divide that by 2 to get 9. You have 9 treadmills. Finally, you'd plug 9 in for x in the equation y=x+7, to get 16 for stationary bikes.
  2. 16 January, 02:53
    0
    25 - 7

    I would do this step because I know that there are 7 more stationary bikes than treadmills, later I would add seven to the stationary bikes.

    I would get the answer of 18 = 25 - 7

    Next I would divide 18 by 2 because there are only two objects in this word problem

    There are 9 treadmills and doing 9 plus 7 would get me 16 stationary bikes because they have 7 more than the treadmills

    16 Stationary Bikes

    9 Treadmills
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