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15 August, 10:22

A certain television is advertised as a 58-inch TV (the diagonal length). If the width of the TV is 42 inches, how many inches tall is the TV?

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Answers (2)
  1. 15 August, 13:31
    0
    Your answer will be 16
  2. 15 August, 13:48
    0
    The height of the television is:

    40 inches.

    Step-by-step explanation:

    To solve the proposed exercise you must understand two things:

    Since the flat figure of a television is a rectangle, it can be subdivided into a right triangle (since it has at least a 90 ° angle) A variation of the Pythagorean Triangle will be used.

    The Pythagorean triangle tells us that the sum of the base squared and the height squared of a right triangle will be equal to the hypotenuse (diagonal) squared of the triangle, which is usually expressed like this:

    a^2 + b^2 = c^2

    But to make it more understandable, let's express it like this:

    base^2 + height^2 = diagonal^2

    Since the diagonal and the base (width) of the television are provided in the exercise, we must clear the height and calculate:

    height^2 = diagonal^2 - base^2 height^2 = 58^2 - 42^2 height^2 = 1600

    To identify the value if in the square, you must apply square root to the obtained value:

    height^2 = square root of 1600 height^2 = 40 inches.
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