Consider the graph of the following qyadratic equation. y=x^+4x-5 what is the axis of the symmerty?

The axis of symmetry is at x=-2

Step-by-step explanation:

The axis of symmetry, h, is found at

h = - b/2a where a and b are the coefficients of the equation in standard form

y = ax^2 + bx + c

y = x^2 + 4x+5

a = 1 b=4 c=5

Then

h = - 4/2 (1)

= - 2

The axis of symmetry is at x=-2