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27 November, 17:26

The temperature of a liquid in an experiment starts at 0 degrees. The temperature of the liquid changes at a rate of - 0.2 per minute. How long will it take for the liquid to reach - 14.6 degrees.

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  1. 27 November, 20:15
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    Initial temperature of the liquid = 0 degrees.

    Rate of changes of liquid temperature = - 0.2 per minute.

    Rate of change also represents slope of a linear function.

    We know, slope-intercept form of a linear equation

    y=mx+b, where m is the slope (rate of change) and b is y-intercept (initial temprature).

    With respect to given problem, y represents temperature of a liquid after x number of minutes.

    According to given problem, slope (rate of change) = - 0.2 per minute and y-intercept (initial temprature) = 0.

    Plugging values of m and b in the above slope-intercept form of a linear equation. We get,

    y=-0.2x+0

    or y=-0.2x.

    Final temprature is given - 14.6 degrees and we need to find time when temprature reach - 14.6 degrees.

    As y represents temperature of a liquid, we need to plug y=-14.6 in above equation.

    We get,

    -14.6=-0.2x.

    Dividing both sides by - 0.2.

    -14.6/-0.2=-0.2x/-0.2

    x=73.

    We got 73 minutes.

    73 minutes can be convert in hours.

    We have 60 minutes in an hour.

    Therefore, 73 = 60+13.

    So, 1 hour and 13 minutes will it for the liquid to reach - 14.6 degrees.

    In minutes answer is 73 minutes.
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