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9 January, 01:57

Enter the correct answer in the box. Use the sum of cubes identity to find the factors of the expression 8x^6 + 27y^3

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  1. 9 January, 04:24
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    I need this answer too
  2. 9 January, 04:51
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    (2x^2 + 3y) (4x^4 - 6x^2y + 9y^2).

    Step-by-step explanation:

    a^3 + b^3 = (a + b) (a^2 - ab + b^2) is the identity.

    Comparing this with the sum in the question:

    a = 2x^2 and b = 3y so we have:

    8x^6 + 27y^3 = (2x^2 + 3y) (4x^4 - 2x^2*3y + 9y^2)

    = (2x^2 + 3y) (4x^4 - 6x^2y + 9y^2).
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