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19 May, 11:20

What are the zeros of the function? f (b) = b ^2 - 16b + 64

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  1. 19 May, 12:59
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    b = 8 and b = 8

    Step-by-step explanation:

    f (b) = b² - 16b + 64 is set equal to zero and solved for b:

    f (b) = b² - 16b + 64 = 0

    This quadratic can be factored, as follows: f (b) = (b - 8) (b - 8) = (b - 8) ² = 0

    There are two real, equal zeros: b = 8 and b = 8.
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