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3 June, 11:26

Find three consecutive even integers. Such as that 5 times of the first integer is 18 more than the sum of second and third interferes

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  1. 3 June, 13:16
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    The numbers would be 2, 4, and 6.

    Step-by-step explanation:

    In order to find this, start by setting the lowest number as x. Then we can determine that the next two even integers are x + 2 and x + 4. From this we can write the following equation.

    5 (x) = x + 2 + x + 4

    5x = 2x + 6

    3x = 6

    x = 2

    Since the first number is 2, we know the next two are 4 and 6.
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