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Mathematics
Adalynn Berg
5 February, 01:14
Compute (2i-6) (5+1) where i=√1
+3
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Elliott Parrish
5 February, 02:56
0
Step-by-step explanation:
hello:
(2i-6) (5+i) = 10i+2i²-30-6i ... i² = - 1
(2i-6) (5+i) = 10i-2-30-6i = - 32+4i
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Galvan
5 February, 03:58
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4i - 32
Step-by-step explanation:
(2i-6) (5+i)
10i - 30 + 2i² - 6i
i=√-1
i² = - 1
10i - 30 + 2 (-1) - 6i
-30 - 2 + 10i - 6i
-32 + 4i
4i - 32
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