Solve for the linear system by using substitution

x=6-4y

2x-3y=1

Hey!

So heres how you would go about doing this:

x = 6-4y

2x - 3y = 1

Plug the value of x which is 6 - 4y into the second equation:

2 (6 - 4y) - 3y = 1

12 - 8y - 3y = 1

12 - 11y = 1

-11y = - 11

y = 1

Now plug this back into the first equation which gives you x's value:

x = 6 - 4y

x = 6 - 4 (1)

x = 6 - 4

x = 2

The answer is:

x = 2

y = 1