Find the 35th term of the sequence given: (3, 14, 25, ...)

Find the 35th term of the sequence given: (3, 14, 25, ...)

377 = a (35)

Step-by-step explanation:

This is an arithmetic sequence with first term 3 and common differernce 11. Notice how each new term is equal to the previous term, plus 11.

So we have a (n) = 3 + 11 (n - 1), and here that becomes

a (35) = 3 + 11 (35 - 1) = 3 + 11 (34) = 3 + 374 = 377 = a (35)