A bag contains 3 red marbles, 6 blue marbles and 2 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be green?

Question

Mathematics

Tucker

24 June, 20:56

A bag contains 3 red marbles, 6 blue marbles and 2 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be green?

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Answers (2)

Know the Answer?

Khloe Scott · Answer 1

answer is 27%

Carmen Todd · Answer 2

Answer: 18%

Step-by-step explanation:

add all of the marbles together, there are 11 total marbles. divide the total marbles with how many green marbles there are in the bag, 2/11, Which will give you 0.1818182. reduce that to the nearest tenth ... 0.18. So there is an 18% chance that both marbles drawn will be green.