Whlch set of numbers contains both solutions to the equation x2 - 2x - 8 = 0?

Answer: x = {-2, 4}

Step-by-step explanation:

0 = x² - 2x - 8

∧

1 - 8 = - 7

2 - 4 = - 2 This works because the b-value is - 2!

0 = (x + 2) (x - 4)

0 = x + 2 0 = x - 4

x = - 2 x = 4