A water balloon is 5 feet above the ground when Sally launches it into the air. Use the quadratic equation 0 = - t2 + 4t + 5 to find how much time, t, it takes for the water balloon to reach the ground.

Question

Mathematics

Jamari Landry

13 November, 07:35

A water balloon is 5 feet above the ground when Sally launches it into the air. Use the quadratic equation 0 = - t2 + 4t + 5 to find how much time, t, it takes for the water balloon to reach the ground.

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Answers (1)

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Stormy · Answer 1

2-sqrt14/2, 2+sqrt13/2.

Step-by-step explanation:

What you do is you have to do the quadratic equation like it says in the problem.

x = - b± sqrtb^2 - 4ac / 2a.

a=-2, b=4, c=5.

x=-4±sqrt (4) ^2-4 (-2) (5) / 2 (-2).

x=-4±sqrt16+40/-4.

x=-4±2sqrt14/-2.

2-sqrt14/2, 2+sqrt13/2. is your answer once you have done everything.