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29 December, 19:10

Find three consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen

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  1. 29 December, 19:23
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    Let the first integer be x, then second = x+2 and third = x + 4 and

    2 (x + x+4) = x + 2 + 15

    4x + 8 = x + 17

    3x = 17 - 8 = 9

    x = 3

    So the required numbers are 3, 5. and 7 (answer)
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