Which of the following are solutions to the quadratic equation? Check all that

apply.

2x2 + 6x-10 = x2 + 6

A. - 8

B. 1/3

C. 2

D. - 2

E. 8

F. - 1/2

A and C

Step-by-step explanation:

Given

2x² + 6x - 10 = x² + 6 (subtract x² + 6 from both sides)

x² + 6x - 16 = 0

Consider the factors of the constant term ( - 16) which sum to give the coefficient of the x - term ( + 6)

The factors are + 8 and - 2, since

8 * - 2 = - 16 and 8 - 2 = + 6, thus

(x + 8) (x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8 → A

x - 2 = 0 ⇒ x = 2 → C