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12 October, 23:52

The area of a rectangle is 52in^2 the length of the rectangle is 9 in longer than the width what is the width

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  1. 13 October, 03:25
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    Area (A) = 52in^2

    Width (W) = ?

    Length (L) = W+9

    Area = LxW

    52 = (W+9) (W)

    52=W^2 + 9W

    0 = W^2 + 9W-52

    0 = (W+13) (W-4)

    W+13=0 then W=-13 and W-4=0 then W=4

    We will only use the positive solution of 4 since distance is positive.

    W=4
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