If 5 (4 - x) < y + 12 and y + 12 < 3x + 1, then which statement is true?

5 (4 - x) < 3x + 1

5 (4 - x) + 3x + 1 = y + 12

3x + 1 < 5 (4 + x)

3x + 1 - 5 (4 - x) = y + 12

5 (4 - x) < 3x + 1

Step-by-step explanation:

Since 5 (4 - x) has a value less than y + 12, and 3x + 1 has a value greater than y + 12, the transitive property can relate the two expressions in a single inequality.

The transitive property of inequality is stated below.

If a < b and b < c, then a < c.

So, the statement 5 (4 - x) < 3x + 1 is true.

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