Ask Question
Today, 03:05

Solve each system of equations by substitution or elimination.

y=x^2-2x-1

y=-x^2-2x-1

Show all steps and explain what method you chose.

+1
Answers (1)
  1. Today, 06:13
    0
    x = 0, y = - 1.

    Step-by-step explanation:

    y = x^2 - 2x - 1

    y = - x^2 - 2x - 1

    Use elimination:

    Subtract the 2 equations:

    0 = x^2 - (-x^2) - 2x - (-2x) - 1 - (-1)

    Simplifying:

    0 = x^2 + x^2 - 2x + 2x - 1 + 1

    0 = 2x^2

    x = 0.

    Substitute this into the first equation:

    y = 0^2 - 2 (0) - 1

    y = - 1.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solve each system of equations by substitution or elimination. y=x^2-2x-1 y=-x^2-2x-1 Show all steps and explain what method you chose. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers