If'f (x) = 2x^2-x-6' and 'g (x) = x^2-4', find 'f (x) - : g (x) '.

a. ' (2x+3) / (x-2) '

b. ' (2x-3) / (x+2) '

c. ' (2x+3) / (x+2) '

d. ' (2x-3) / (x-2) '

First factor 2x² - x - 6 to get (2x + 3) (x - 2)

Then place f (x) in the numerator and g (x) in the denominator.

(2x + 3) (x-2)

(x + 2) (x-2)

Cancel out (x-2) in the numerator and denominator

Then your answer will be (2x + 3) / (x + 2)