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9 August, 22:48

Determine the number of zeros of the polynomial function. h (t) = (t - 6) 2 - (t + 6) 2

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  1. 10 August, 00:40
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    Step-by-step explanation:

    (t - 6) ^2 = t^2 - 12t + 36

    (t + 6) ^2 = t^2 + 12t + 36

    (t - 6) ^2 - (t + 6) = t^2 - 12t + 36 - (t^2 + 12t + 36)

    (t - 6) ^2 - (t + 6) = t^2 - 12t + 36 - t^2 - 12t - 36

    (t - 6) ^2 - (t + 6) = - 24t The other 4 terms cancel out.

    -24t = 0 Divide by - 24

    t = 0

    There is one root.
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