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23 December, 13:37

Use the technique developed in this section to solve the minimization problem. Minimize C = - 3x - 2y - z subject to - x + 2y - z ≤ 20 x - 2y + 2z ≤ 25 2x + 4y - 3z ≤ 30 x ≥ 0, y ≥ 0, z ≥ 0 The minimum is C = at (x, y, z) =.

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  1. 23 December, 16:58
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    C = - 145, (35/4, 295/8, 45)

    Step-by-step explanation:

    Use Gaussian elimination to find the values of x, y and z

    Eq 1: - x+2y-z=20

    Eq 2: x-2y+2z=25

    Eq 3: 2x+4y-3z=30

    Multily Eq1 by 1 and add to Eq 2

    Eq 1: (-x+2y-z=20) * 1

    Eq 2: x-2y+2z=25

    Eq 3: 2x+4y-3z=30

    ⇒ Eq1: - x+2y-z=20

    Eq2: z = 45

    Eq 3: 2x+4y-3z=30

    Multiply Eq 1 by 2 and then add to Eq 3

    Eq1: (-x+2y-z=20) * 2

    Eq2: z = 45

    Eq3: 2x+4y-3z=30

    ⇒ Eq1: - x+2y-z=20

    Eq2: z = 45

    Eq3: 8y-5z = 70

    swap Eq 2 and Eq 3

    Eq 1: - x+2y-z=20

    Eq 3: 8y-5z = 70

    Eq 2: z = 45

    Solve Eq 2 for z

    Z=45

    solve Eq Eq 3 for y.

    y = 295/8

    Using the value z=45 and y = 295/8, substitue in Eq 1 to get value of x

    x = 35/4

    Substitue values of x, y and z in C = - 3x-2y-z to get minimum value of C

    C = - 145
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