What are the zeros of the function f (x) = x^2 + 2x - 24?

The zeros are 4 and - 6

Step-by-step explanation:

f (x) = x^2 + 2x - 24

Start by factoring so the equation looks like this: f (x) = (x + _) (x - _)

When you factor, you need to find two numbers that add to the middle term and multiply to equal the last term.

Two numbers that work are - 4 and 6.

-4 + 6 = 2 (so that works for the middle term) and - 4 * 6 = - 24 (that works for the last term)

When you put those numbers in the parentheses, it looks like this:

f (x) = (x + 6) (x - 4)

Make both equal to 0 and solve for x: x + 6 = 0, x - 4 = 0

x = - 6, x = 4