Three consecutive numbers have a sum of 36. What are the numbers?

11,12,13

Step-by-step explanation:

x is the first number

x+1 is the second number

x+2 is the third number

x + x+1+x+2 = 36

Combine like terms

3x+3 = 36

Subtract 3 from each side

3x+3-3 = 36-3

3x = 33

Divide by 3

3x/3 = 33/3

x = 11

The numbers are 11, 11+1, 11+2

11,12,13