Find the vertex, zero and y-intercept of the graph of y=x^2 - 6x+8

vertex: (3, - 1) and zeros: x = 4, x = 2 and y-int: y = - 1

Step-by-step explanation:

y = xx - 6x + 8

y = (x - 4) (x - 2)

since - 4 * - 2 = 8

and - 4 + - 2 = - 6

so roots are x = 4 and x = 2

y = xx - 6x + 9 - 9 + 8

y = (x - 3) ^2 - 1

vertex: (3, - 1)

y-int: y = - 1