Ask Question
6 November, 18:23

Find a, b such that 7.2, a, b, 3 are in A. P.

+3
Answers (1)
  1. 6 November, 19:12
    0
    a = 5.8 b = 4.4

    Step-by-step explanation:

    As

    7.2, a, b, 3 are in A. P

    As we know common difference of the arithmetic sequence is the difference between the successive term and its preceding term, which is always constant

    so

    a - 7.2 = b - a

    a + a = b + 7.2

    2a = b + 7.2

    b = 2a - 7.2

    also

    a, b, 3 are in A. P

    b - a = 3 - b

    b + b = 3 + a

    2b = 3 + a

    Putting b = 2a - 7.2 in the equation 2b = 3 + a to find the value of 'a'.

    2b = 3 + a

    2 (2a - 7.2) = 3 + a

    4a - 14.4 = 3 + a

    3a = 3 + 14.4

    3a = 17.4

    Dividing the equation by 3

    3a : 3 = 17.4 : 3

    a = 5.8

    Putting a = 5.8 in the equation b = 2a - 7.2

    b = 2a - 7.2

    = 2 (5.8) - 7.2

    = 11.6 - 7.2

    b = 4.4

    Therefore,

    a = 5.8 b = 4.4
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Find a, b such that 7.2, a, b, 3 are in A. P. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers