Solve the system of equations.

y = 3x

y = x2-10

(-5, 2) and (2, 6)

Step-by-step explanation:

Use the substitution method. We know that y = 3x and y = x^2 - 10, so we can set them equal to one another.

3x = x^2 - 10

x^2 - 3x - 10 = 0

Use the quadratic equation to solve for x.

x = - 5, 2

Now solve for y using these two values of x by substituting it back into the equations.

y = - 15, 6

In coordinate form, (-5, 2) and (2, 6)