Factor x^3 - 4x^2 - 3x + 18 = 0

Given that 4 is a zero

A (x-2) (x-3) (x+3) = 0

B (x-2) (x-3) ^2 = 0

C (x-2) (x - sqrt 3) (x + sqrt 3) = 0

D (x-2) (x-3) ^2 = 0

none of the above

Step-by-step explanation:

A graphing calculator shows the zeros to be x=-2, and a double zero at x=3. Hence the factorization is ...

(x + 2) (x - 3) ^2 = 0

The premise that 4 is a zero is incorrect, and none of the answer choices include (x+2) as a factor. The problem is unworkable as written here.