Three irrational number whose sum is a rational number.

sqrt (2)

sqrt (3)

6 - sqrt (2) sqrt (3)

Step-by-step explanation:

sqrt (2) is an irrational number.

sqrt (3) is an irrational number.

Let x = 6 - sqrt (2) - sqrt (3).

x is also an irrational number.

Now add the three numbers above:

sqrt (2) + sqrt (3) + [6 - sqrt (2) - sqrt (3) ] =

= sqrt (2) + sqrt (3) + 6 - sqrt (2) - sqrt (3)

= 6