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Mathematics
Camren Cowan
15 June, 11:19
2cos^2x = 1
Solve for 0-360 degrees
+1
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Chana
15 June, 13:04
0
45°, 135°, 225°, 315°
Step-by-step explanation:
2cos²x = 1
cos²x = ½
cosx = + / - 1/sqrt (2)
Basic angle: 45
Since cos has both, positive and negative values, we'll consider all 4 quadrants
45,
180 - 45 = 135
180 + 45 = 225
360 - 45 = 315
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Beatrice Henson
15 June, 14:20
0
45,135,315,225
Step-by-step explanation:
2cos^2x = 1
Divide each side by 2
cos^2x = 1/2
Take the square root of each side
sqrt (cos^2 x) = ±sqrt (1/2)
cos x = ±sqrt (1/2)
Make into two separate equations
cos x = sqrt (1/2) cos x = - sqrt (1/2)
Take the inverse cos of each side
cos ^-1 cos (x) = cos ^-1 (sqrt (1/2)) cos ^-1 cos (x) = cos ^-1 (-sqrt (1/2))
x = cos ^-1 (sqrt (1/2)) x = cos ^-1 (-sqrt (1/2))
x = 45 + 360 n x = 135 + 360n
x = 315+360 n x = 225+360n
Between 0 and 360
45,135,315,225
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